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Within LTS Haskell 24.33 (ghc-9.10.3)
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(
++ ) :: forall (n :: Nat) a (m :: Nat) . Vec n a -> Vec m a -> Vec (n + m) aclash-prelude Clash.Sized.Vector Append two vectors.
>>> (1:>2:>3:>Nil) ++ (7:>8:>Nil) 1 :> 2 :> 3 :> 7 :> 8 :> Nil
(
+>> ) :: forall (n :: Nat) a . KnownNat n => a -> Vec n a -> Vec n aclash-prelude Clash.Sized.Vector Add an element to the head of a vector, and extract all but the last element.
>>> 1 +>> (3:>4:>5:>Nil) 1 :> 3 :> 4 :> Nil >>> 1 +>> Nil Nil
type family (as :: [k])
++ (bs :: [k]) :: [k]generic-lens-core Data.Generics.Product.Internal.HList No documentation available.
(
++/ ) :: DerivPathI t1 -> DerivPathI t2 -> DerivPathhaskoin-core Haskoin.Crypto.Keys.Extended Append two derivation paths together. The result will be a mixed derivation path.
type family (es :: [Effect])
++ (es' :: [Effect]) :: [Effect]heftia Control.Monad.Hefty No documentation available.
(
+/+ ) :: String -> String -> Stringhttp-directory Network.HTTP.Directory This +/+ eats extra slashes.
"dir//" +/+ "/subdir/" = "dir/subdir/"
-
ihaskell IHaskellPrelude No documentation available.
(
+## ) :: Double# -> Double# -> Double#ihaskell IHaskellPrelude No documentation available.
-
ihaskell IHaskellPrelude (++) appends two lists, i.e.,
[x1, ..., xm] ++ [y1, ..., yn] == [x1, ..., xm, y1, ..., yn] [x1, ..., xm] ++ [y1, ...] == [x1, ..., xm, y1, ...]
If the first list is not finite, the result is the first list.Performance considerations
This function takes linear time in the number of elements of the first list. Thus it is better to associate repeated applications of (++) to the right (which is the default behaviour): xs ++ (ys ++ zs) or simply xs ++ ys ++ zs, but not (xs ++ ys) ++ zs. For the same reason concat = foldr (++) [] has linear performance, while foldl (++) [] is prone to quadratic slowdownExamples
>>> [1, 2, 3] ++ [4, 5, 6] [1,2,3,4,5,6]
>>> [] ++ [1, 2, 3] [1,2,3]
>>> [3, 2, 1] ++ [] [3,2,1]
-
incipit-base Incipit.Base (++) appends two lists, i.e.,
[x1, ..., xm] ++ [y1, ..., yn] == [x1, ..., xm, y1, ..., yn] [x1, ..., xm] ++ [y1, ...] == [x1, ..., xm, y1, ...]
If the first list is not finite, the result is the first list.Performance considerations
This function takes linear time in the number of elements of the first list. Thus it is better to associate repeated applications of (++) to the right (which is the default behaviour): xs ++ (ys ++ zs) or simply xs ++ ys ++ zs, but not (xs ++ ys) ++ zs. For the same reason concat = foldr (++) [] has linear performance, while foldl (++) [] is prone to quadratic slowdownExamples
>>> [1, 2, 3] ++ [4, 5, 6] [1,2,3,4,5,6]
>>> [] ++ [1, 2, 3] [1,2,3]
>>> [3, 2, 1] ++ [] [3,2,1]