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  1. enumerateFromTo :: forall (m :: Type -> Type) . (Enumerable a, Monad m) => a -> a -> Stream m a

    streamly-core Streamly.Internal.Data.Stream

    Generate a finite stream starting with the element from, enumerating the type up to the value to. If to is smaller than from then an empty stream is returned.

    >>> Stream.toList $ Stream.enumerateFromTo 0 4
    [0,1,2,3,4]
    
    For Fractional types, the last element is equal to the specified to value after rounding to the nearest integral value.
    >>> Stream.toList $ Stream.enumerateFromTo 1.1 4
    [1.1,2.1,3.1,4.1]
    
    >>> Stream.toList $ Stream.enumerateFromTo 1.1 4.6
    [1.1,2.1,3.1,4.1,5.1]
    

  2. enumerateFromToFractional :: forall (m :: Type -> Type) a . (Monad m, Fractional a, Ord a) => a -> a -> Stream m a

    streamly-core Streamly.Internal.Data.Stream

    Numerically stable enumeration from a Fractional number to a given limit. enumerateFromToFractional from to generates a finite stream whose first element is from and successive elements are in increments of 1 up to to. This is the equivalent of enumFromTo for Fractional types. For example:

    >>> Stream.toList $ Stream.enumerateFromToFractional 1.1 4
    [1.1,2.1,3.1,4.1]
    
    >>> Stream.toList $ Stream.enumerateFromToFractional 1.1 4.6
    [1.1,2.1,3.1,4.1,5.1]
    
    Notice that the last element is equal to the specified to value after rounding to the nearest integer.

  3. enumerateFromToIntegral :: forall (m :: Type -> Type) a . (Monad m, Integral a) => a -> a -> Stream m a

    streamly-core Streamly.Internal.Data.Stream

    Enumerate an Integral type up to a given limit. enumerateFromToIntegral from to generates a finite stream whose first element is from and successive elements are in increments of 1 up to to.

    >>> Stream.toList $ Stream.enumerateFromToIntegral 0 4
    [0,1,2,3,4]
    

  4. enumerateFromToSmall :: forall (m :: Type -> Type) a . (Monad m, Enum a) => a -> a -> Stream m a

    streamly-core Streamly.Internal.Data.Stream

    enumerateFromTo for Enum types not larger than Int.

  5. enumerateTo :: forall (m :: Type -> Type) a . (Monad m, Bounded a, Enumerable a) => a -> Stream m a

    streamly-core Streamly.Internal.Data.Stream

    >>> enumerateTo = Stream.enumerateFromTo minBound
    
    Enumerate a Bounded type from its minBound to specified value.

  6. enumerateFrom :: forall (m :: Type -> Type) . (Enumerable a, Monad m) => Unfold m a a

    streamly-core Streamly.Internal.Data.Unfold

    Unfolds from generating a stream starting with the element from, enumerating up to maxBound when the type is Bounded or generating an infinite stream when the type is not Bounded.

    >>> Stream.toList $ Stream.take 4 $ Stream.unfold Unfold.enumerateFrom (0 :: Int)
    [0,1,2,3]
    
    For Fractional types, enumeration is numerically stable. However, no overflow or underflow checks are performed.
    >>> Stream.toList $ Stream.take 4 $ Stream.unfold Unfold.enumerateFrom 1.1
    [1.1,2.1,3.1,4.1]
    
    Pre-release

  7. enumerateFromFractional :: forall (m :: Type -> Type) a . (Monad m, Fractional a) => Unfold m a a

    streamly-core Streamly.Internal.Data.Unfold

    No documentation available.

  8. enumerateFromIntegral :: forall (m :: Type -> Type) a . (Monad m, Integral a) => Unfold m a a

    streamly-core Streamly.Internal.Data.Unfold

    No documentation available.

  9. enumerateFromIntegralBounded :: forall (m :: Type -> Type) a . (Monad m, Integral a, Bounded a) => Unfold m a a

    streamly-core Streamly.Internal.Data.Unfold

    No documentation available.

  10. enumerateFromNum :: forall (m :: Type -> Type) a . (Monad m, Num a) => Unfold m a a

    streamly-core Streamly.Internal.Data.Unfold

    Same as enumerateFromStepNum using a stride of 1:

    >>> enumerateFromNum = lmap (from -> (from, 1)) Unfold.enumerateFromStepNum
    >>> Stream.toList $ Stream.take 6 $ Stream.unfold enumerateFromNum (0.9)
    [0.9,1.9,2.9,3.9,4.9,5.9]
    
    Also, same as enumerateFromThenNum using a stride of 1 but see the note in enumerateFromThenNum about the loss of precision:
    >>> enumerateFromNum = lmap (from -> (from, from + 1)) Unfold.enumerateFromThenNum
    >>> Stream.toList $ Stream.take 6 $ Stream.unfold enumerateFromNum (0.9)
    [0.9,1.9,2.9,3.8999999999999995,4.8999999999999995,5.8999999999999995]
    
    Internal

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