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1. map :: (a -> b) -> InputStream a -> IO (InputStream b)

   io-streams	System.IO.Streams.Combinators

   Maps a pure function over an InputStream. map f s passes all output from s through the function f. Satisfies the following laws:

   Streams.map (g . f) === Streams.map f >=> Streams.map g
   Streams.map id === Streams.makeInputStream . Streams.read
   

2. map :: (v1 -> v2) -> KeyMap v1 -> KeyMap v2

   autodocodec	Autodocodec.Aeson.Compat

   No documentation available.

3. map :: (Word8 -> Word8) -> ByteString -> ByteString

   rio	RIO.ByteString

   O(n) map f xs is the ByteString obtained by applying f to each element of xs.

4. map :: (Word8 -> Word8) -> ByteString -> ByteString

   rio	RIO.ByteString.Lazy

   O(n) map f xs is the ByteString obtained by applying f to each element of xs.

5. map :: (v1 -> v2) -> HashMap k v1 -> HashMap k v2

   rio	RIO.HashMap

   Transform this map by applying a function to every value.

6. map :: (Hashable b, Eq b) => (a -> b) -> HashSet a -> HashSet b

   rio	RIO.HashSet

   Transform this set by applying a function to every value. The resulting set may be smaller than the source.

   >>> HashSet.map show (HashSet.fromList [1,2,3])
   HashSet.fromList ["1","2","3"]
   

7. map :: (a -> b) -> [a] -> [b]

   rio	RIO.List

   map f xs is the list obtained by applying f to each element of xs, i.e.,

   map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn]
   map f [x1, x2, ...] == [f x1, f x2, ...]
   

   this means that map id == id

   Examples

   >>> map (+1) [1, 2, 3]
   [2,3,4]
   

   >>> map id [1, 2, 3]
   [1,2,3]
   

   >>> map (\n -> 3 * n + 1) [1, 2, 3]
   [4,7,10]
   

8. map :: (a -> b) -> Map k a -> Map k b

   rio	RIO.Map

   Map a function over all values in the map.

   map (++ "x") (fromList [(5,"a"), (3,"b")]) == fromList [(3, "bx"), (5, "ax")]
   

9. map :: (a -> b) -> NonEmpty a -> NonEmpty b

   rio	RIO.NonEmpty

   Map a function over a NonEmpty stream.

10. map :: (a -> b) -> [a] -> [b]

    rio	RIO.Prelude

    map f xs is the list obtained by applying f to each element of xs, i.e.,

    map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn]
    map f [x1, x2, ...] == [f x1, f x2, ...]
    

    this means that map id == id

    Examples

    >>> map (+1) [1, 2, 3]
    [2,3,4]
    

    >>> map id [1, 2, 3]
    [1,2,3]
    

    >>> map (\n -> 3 * n + 1) [1, 2, 3]
    [4,7,10]
    

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