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Within LTS Haskell 24.4 (ghc-9.10.2)

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  1. evaluateHead :: NormalForm sig => sig -> ()

    synthesizer-core Synthesizer.Generic.Cut

    Evaluating the first value of the signal is necessary for avoiding a space leaks if you repeatedly drop a prefix from the signal and do not consume something from it.

  2. evaluate_ :: (MonadDOM m, IsDocument self, ToJSString expression, IsNode contextNode) => self -> Maybe expression -> Maybe contextNode -> Maybe XPathNSResolver -> Maybe Word -> Maybe XPathResult -> m ()

    ghcjs-dom GHCJS.DOM.Document

    Mozilla Document.evaluate documentation

  3. evaluateDerivative :: InterpolationMethod -> [(Double, Double)] -> Double -> Double

    hmatrix-gsl Numeric.GSL.Interpolation

    Evaluate the derivative of a function by interpolating within the given dataset. For example:

    >>> let xs = [1..10]
    
    >>> let ys map (**2) [1..10]
    
    >>> evaluateDerivative Akima (zip xs ys) 2.2
    4.4
    
    To successfully evaluateDerivative points x, the domain (x) values in points must be monotonically increasing. The evaluation point x must lie between the smallest and largest values in the sampled domain.

  4. evaluateDerivative2 :: InterpolationMethod -> [(Double, Double)] -> Double -> Double

    hmatrix-gsl Numeric.GSL.Interpolation

    Evaluate the second derivative of a function by interpolating within the given dataset. For example:

    >>> let xs = [1..10]
    
    >>> let ys map (**2) [1..10]
    
    >>> evaluateDerivative2 Akima (zip xs ys) 2.2
    2.0
    
    To successfully evaluateDerivative2 points x, the domain (x) values in points must be monotonically increasing. The evaluation point x must lie between the smallest and largest values in the sampled domain.

  5. evaluateDerivative2V :: InterpolationMethod -> Vector Double -> Vector Double -> Double -> Double

    hmatrix-gsl Numeric.GSL.Interpolation

    Evaluate the second derivative of a function by interpolating within the given dataset. For example:

    >>> let xs = vector [1..10]
    
    >>> let ys = vector $ map (**2) [1..10]
    
    >>> evaluateDerivative2V CSpline xs ys 2.2
    2.4
    
    To successfully evaluateDerivative2V xs ys x, the vectors xs and ys must have identical lengths, and xs must be monotonically increasing. The evaluation point x must lie between the smallest and largest values in xs.

  6. evaluateDerivativeV :: InterpolationMethod -> Vector Double -> Vector Double -> Double -> Double

    hmatrix-gsl Numeric.GSL.Interpolation

    Evaluate the derivative of a function by interpolating within the given dataset. For example:

    >>> let xs = vector [1..10]
    
    >>> let ys = vector $ map (**2) [1..10]
    
    >>> evaluateDerivativeV CSpline xs ys 2.2
    4.338867924528302
    
    To successfully evaluateDerivativeV xs ys x, the vectors of corresponding domain-range values xs and ys must have identical lengths, and xs must be monotonically increasing. The interpolation point x must lie between the smallest and largest values in xs.

  7. evaluateIntegral :: InterpolationMethod -> [(Double, Double)] -> (Double, Double) -> Double

    hmatrix-gsl Numeric.GSL.Interpolation

    Evaluate the definite integral of a function by interpolating within the given dataset. For example:

    >>> let xs = [1..10]
    
    >>> let ys = map (**2) [1..10]
    
    >>> evaluateIntegralV CSpline (zip xs ys) (2.2, 5.5)
    51.909
    
    To successfully evaluateIntegral points (a, b), the domain (x) values of points must be monotonically increasing. The integration bounds a and b must lie between the smallest and largest values in the sampled domain..

  8. evaluateIntegralV :: InterpolationMethod -> Vector Double -> Vector Double -> Double -> Double -> Double

    hmatrix-gsl Numeric.GSL.Interpolation

    Evaluate the definite integral of a function by interpolating within the given dataset. For example:

    >>> let xs = vector [1..10]
    
    >>> let ys = vector $ map (**2) [1..10]
    
    >>> evaluateIntegralV CSpline xs ys 2.2 5.5
    51.89853207547169
    
    To successfully evaluateIntegralV xs ys a b, the vectors xs and ys must have identical lengths, and xs must be monotonically increasing. The integration bounds a and b must lie between the smallest and largest values in xs.

  9. evaluateV :: InterpolationMethod -> Vector Double -> Vector Double -> Double -> Double

    hmatrix-gsl Numeric.GSL.Interpolation

    Evaluate a function by interpolating within the given dataset. For example:

    >>> let xs = vector [1..10]
    
    >>> let ys = vector $ map (**2) [1..10]
    
    >>> evaluateV CSpline xs ys 2.2
    4.818867924528303
    
    To successfully evaluateV xs ys x, the vectors of corresponding domain-range values xs and ys must have identical lengths, and xs must be monotonically increasing. The evaluation point x must lie between the smallest and largest values in xs.

  10. evaluateDatabase :: MigrationSteps be () a -> a

    beam-migrate Database.Beam.Migrate.Types

    Run a MigrationSteps without executing any of the commands against a database.

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