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Within LTS Haskell 24.58 (ghc-9.10.3)

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1. createModuleExWithFixities :: [(String, Fixity)] -> Located (HsModule GhcPs) -> ModuleEx

   hlint	Language.Haskell.HLint

   No documentation available.

2. fixities :: ParseFlags -> [FixityInfo]

   hlint	Language.Haskell.HLint

   List of fixities to be aware of, defaults to those defined in base.

3. parseFlagsAddFixities :: [FixityInfo] -> ParseFlags -> ParseFlags

   hlint	Language.Haskell.HLint

   Given some fixities, add them to the existing fixities in ParseFlags.

4. isInfixOf :: ByteString -> ByteString -> Bool

   rio	RIO.ByteString

   Check whether one string is a substring of another.

5. isPrefixOf :: ByteString -> ByteString -> Bool

   rio	RIO.ByteString

   O(n) The isPrefixOf function takes two ByteStrings and returns True if the first is a prefix of the second.

6. isSuffixOf :: ByteString -> ByteString -> Bool

   rio	RIO.ByteString

   O(n) The isSuffixOf function takes two ByteStrings and returns True iff the first is a suffix of the second. The following holds:

   isSuffixOf x y == reverse x `isPrefixOf` reverse y
   

   However, the real implementation uses memcmp to compare the end of the string only, with no reverse required..

7. stripPrefix :: ByteString -> ByteString -> Maybe ByteString

   rio	RIO.ByteString

   O(n) The stripPrefix function takes two ByteStrings and returns Just the remainder of the second iff the first is its prefix, and otherwise Nothing.

8. stripSuffix :: ByteString -> ByteString -> Maybe ByteString

   rio	RIO.ByteString

   O(n) The stripSuffix function takes two ByteStrings and returns Just the remainder of the second iff the first is its suffix, and otherwise Nothing.

9. isPrefixOf :: ByteString -> ByteString -> Bool

   rio	RIO.ByteString.Lazy

   O(n) The isPrefixOf function takes two ByteStrings and returns True iff the first is a prefix of the second.

10. isSuffixOf :: ByteString -> ByteString -> Bool

    rio	RIO.ByteString.Lazy

    O(n) The isSuffixOf function takes two ByteStrings and returns True iff the first is a suffix of the second. The following holds:

    isSuffixOf x y == reverse x `isPrefixOf` reverse y
    

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