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Within Stackage Nightly 2024-05-15 (ghc-9.8.2)

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1. (>>=) :: Monad m => m a -> (a -> m b) -> m b

   base	Prelude

   Sequentially compose two actions, passing any value produced by the first as an argument to the second. 'as >>= bs' can be understood as the do expression

   do a <- as
   bs a
   

2. (>>=) :: Monad m => m a -> (a -> m b) -> m b

   base	Control.Monad

   Sequentially compose two actions, passing any value produced by the first as an argument to the second. 'as >>= bs' can be understood as the do expression

   do a <- as
   bs a
   

3. (>>=) :: Monad m => m a -> (a -> m b) -> m b

   base	Control.Monad.Instances

   Sequentially compose two actions, passing any value produced by the first as an argument to the second. 'as >>= bs' can be understood as the do expression

   do a <- as
   bs a
   

4. (>>=) :: Monad m => m a -> (a -> m b) -> m b

   base	GHC.Base

   Sequentially compose two actions, passing any value produced by the first as an argument to the second. 'as >>= bs' can be understood as the do expression

   do a <- as
   bs a
   

5. (>>=) :: Monad m => m a -> (a -> Code m b) -> Code m b

   template-haskell	Language.Haskell.TH.CodeDo

   Module over monad operator for Code

6. (>>=) :: Monad m => m a -> (a -> m b) -> m b

   hedgehog	Hedgehog.Internal.Prelude

   Sequentially compose two actions, passing any value produced by the first as an argument to the second. 'as >>= bs' can be understood as the do expression

   do a <- as
   bs a
   

7. (>>=) :: Bind m => m a -> (a -> m b) -> m b

   semigroupoids	Semigroupoids.Do

   No documentation available.

8. (>>=) :: Monad m => m a -> (a -> m b) -> m b

   ghc	GHC.Prelude.Basic

   Sequentially compose two actions, passing any value produced by the first as an argument to the second. 'as >>= bs' can be understood as the do expression

   do a <- as
   bs a
   

9. (>>=) :: Monad m => m a -> (a -> m b) -> m b

   haskell-gi-base	Data.GI.Base.ShortPrelude

   Sequentially compose two actions, passing any value produced by the first as an argument to the second. 'as >>= bs' can be understood as the do expression

   do a <- as
   bs a
   

10. (>>=) :: Monad m => m a -> (a -> m b) -> m b

    rio	RIO.Prelude

    Sequentially compose two actions, passing any value produced by the first as an argument to the second. 'as >>= bs' can be understood as the do expression

    do a <- as
    bs a
    

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