Haskell library containing common graph search algorithms
Lots of problems can be modeled as graphs, but oftentimes one doesn't want to use an explicit graph structure to represent the problem. Maybe the graph would be too big (or is infinite), maybe making an explicit graph is unwieldy for the problem at hand, or maybe one just wants to generalize over graph implementations. That's where this library comes in: this is a collection of generalized search algorithms, so that one doesn't have to make the graphs explicit. In general, this means that one provides each search function with a function to generate neighboring states, a list of predicates which tell whether a "dead end" has been reached, a predicate which tells when the search is complete, and an initial state to start from. The result is a path from the initial state to a "solved" state, or
Nothing if no such path is possible.
import Algorithm.Search (bfs) countChange target = bfs add_one_coin [(> target)] (== target) 0 where add_one_coin amt = map (+ amt) coins coins = [1, 5, 10, 25] -- countChange gives the subtotals along the way to the end: -- >>> countChange 67 -- Just [1, 2, 7, 17, 42, 67]
Simple directed acyclic graph:
import Algorithm.Search (dfs) import qualified Data.Map as Map graph = Map.fromList [ (1, [2, 3]), (2, ), (3, ), (4, ) ] -- Run dfs on the graph: -- >>> dfs (graph Map.!)  (== 4) 1 -- Just [3,4]
Using A* to find a path in an area with a wall:
import Algorithm.Search (aStar) taxicabNeighbors :: (Int, Int) -> [(Int, Int)] taxicabNeighbors (x, y) = [(x, y + 1), (x - 1, y), (x + 1, y), (x, y - 1)] isWall :: (Int, Int) -> Bool isWall (x, y) = x == 1 && (-2) <= y && y <= 1 taxicabDistance :: (Int, Int) -> (Int, Int) -> Int taxicabDistance (x1, y1) (x2, y2) = abs (x2 - x1) + abs (y2 - y1) findPath :: (Int, Int) -> (Int, Int) -> Maybe (Int, [(Int, (Int, Int))]) findPath start end = let next = map (\pt -> (1, taxicabDistance pt end, pt)) . taxicabNeighbors in aStar next [isWall] (== end) start -- findPath p1 p2 finds a path between p1 and p2, avoiding the wall -- >>> findPath (0, 0) (2, 0) -- Just (6,[(1,(0,1)),(1,(0,2)),(1,(1,2)),(1,(2,2)),(1,(2,1)),(1,(2,0))]) -- -- This correctly goes up and around the wall