Hoogle Search
Within LTS Haskell 24.17 (ghc-9.10.3)
Note that Stackage only displays results for the latest LTS and Nightly snapshot. Learn more.
- map :: (a <-> b) -> [a] <-> [b]- invertible - Data.Invertible.Prelude - Apply a bijection over a list using map. 
- map :: forall t (m :: Type -> Type) a b . (IsStream t, Monad m) => (a -> b) -> t m a -> t m b- streamly - Streamly.Prelude - map = fmap Same as fmap.- > D.toList $ D.map (+1) $ D.fromList [1,2,3] [2,3,4] 
- 
constrained-categories Control.Category.Constrained.Prelude map f xs is the list obtained by applying f to each element of xs, i.e., map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn] map f [x1, x2, ...] == [f x1, f x2, ...] this means that map id == idExamples>>> map (+1) [1, 2, 3] [2,3,4] >>> map id [1, 2, 3] [1,2,3] >>> map (\n -> 3 * n + 1) [1, 2, 3] [4,7,10] 
- 
copilot-language Copilot.Language.Prelude map f xs is the list obtained by applying f to each element of xs, i.e., map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn] map f [x1, x2, ...] == [f x1, f x2, ...] this means that map id == idExamples>>> map (+1) [1, 2, 3] [2,3,4] >>> map id [1, 2, 3] [1,2,3] >>> map (\n -> 3 * n + 1) [1, 2, 3] [4,7,10] 
- 
xmonad-contrib XMonad.Prelude map f xs is the list obtained by applying f to each element of xs, i.e., map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn] map f [x1, x2, ...] == [f x1, f x2, ...] this means that map id == idExamples>>> map (+1) [1, 2, 3] [2,3,4] >>> map id [1, 2, 3] [1,2,3] >>> map (\n -> 3 * n + 1) [1, 2, 3] [4,7,10] 
- 
rio RIO.Prelude.Types A Map from keys k to values a. The Semigroup operation for Map is union, which prefers values from the left operand. If m1 maps a key k to a value a1, and m2 maps the same key to a different value a2, then their union m1 <> m2 maps k to a1. 
- 
Cabal-syntax Distribution.Compat.Prelude A Map from keys k to values a. The Semigroup operation for Map is union, which prefers values from the left operand. If m1 maps a key k to a value a1, and m2 maps the same key to a different value a2, then their union m1 <> m2 maps k to a1. 
- type family - Map (a1 :: a ~> b) (a2 :: [a]) :: [b]- singletons-base - Prelude.Singletons - No documentation available. 
- 
rebase Rebase.Prelude A Map from keys k to values a. The Semigroup operation for Map is union, which prefers values from the left operand. If m1 maps a key k to a value a1, and m2 maps the same key to a different value a2, then their union m1 <> m2 maps k to a1. 
- 
cabal-install-solver Distribution.Solver.Compat.Prelude A Map from keys k to values a. The Semigroup operation for Map is union, which prefers values from the left operand. If m1 maps a key k to a value a1, and m2 maps the same key to a different value a2, then their union m1 <> m2 maps k to a1. 
