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map :: (a <-> b) -> [a] <-> [b]invertible Data.Invertible.Prelude Apply a bijection over a list using map.
map :: forall t (m :: Type -> Type) a b . (IsStream t, Monad m) => (a -> b) -> t m a -> t m bstreamly Streamly.Prelude map = fmap
Same as fmap.> D.toList $ D.map (+1) $ D.fromList [1,2,3] [2,3,4]
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constrained-categories Control.Category.Constrained.Prelude map f xs is the list obtained by applying f to each element of xs, i.e.,
map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn] map f [x1, x2, ...] == [f x1, f x2, ...]
this means that map id == idExamples
>>> map (+1) [1, 2, 3] [2,3,4]
>>> map id [1, 2, 3] [1,2,3]
>>> map (\n -> 3 * n + 1) [1, 2, 3] [4,7,10]
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copilot-language Copilot.Language.Prelude map f xs is the list obtained by applying f to each element of xs, i.e.,
map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn] map f [x1, x2, ...] == [f x1, f x2, ...]
this means that map id == idExamples
>>> map (+1) [1, 2, 3] [2,3,4]
>>> map id [1, 2, 3] [1,2,3]
>>> map (\n -> 3 * n + 1) [1, 2, 3] [4,7,10]
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xmonad-contrib XMonad.Prelude map f xs is the list obtained by applying f to each element of xs, i.e.,
map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn] map f [x1, x2, ...] == [f x1, f x2, ...]
this means that map id == idExamples
>>> map (+1) [1, 2, 3] [2,3,4]
>>> map id [1, 2, 3] [1,2,3]
>>> map (\n -> 3 * n + 1) [1, 2, 3] [4,7,10]
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rio RIO.Prelude.Types A Map from keys k to values a. The Semigroup operation for Map is union, which prefers values from the left operand. If m1 maps a key k to a value a1, and m2 maps the same key to a different value a2, then their union m1 <> m2 maps k to a1.
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Cabal-syntax Distribution.Compat.Prelude A Map from keys k to values a. The Semigroup operation for Map is union, which prefers values from the left operand. If m1 maps a key k to a value a1, and m2 maps the same key to a different value a2, then their union m1 <> m2 maps k to a1.
type family
Map (a1 :: a ~> b) (a2 :: [a]) :: [b]singletons-base Prelude.Singletons No documentation available.
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rebase Rebase.Prelude A Map from keys k to values a. The Semigroup operation for Map is union, which prefers values from the left operand. If m1 maps a key k to a value a1, and m2 maps the same key to a different value a2, then their union m1 <> m2 maps k to a1.
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cabal-install-solver Distribution.Solver.Compat.Prelude A Map from keys k to values a. The Semigroup operation for Map is union, which prefers values from the left operand. If m1 maps a key k to a value a1, and m2 maps the same key to a different value a2, then their union m1 <> m2 maps k to a1.