Hoogle Search

Within LTS Haskell 24.22 (ghc-9.10.3)

Note that Stackage only displays results for the latest LTS and Nightly snapshot. Learn more.

  1. (&>) :: Applicative f => f Any -> f Any -> f Any

    xmonad-contrib XMonad.Util.PureX

    Akin to a low precedence <>. Combines applicative effects left-to-right and wrapped Bools with && (instead of ||).

  2. (&&&) :: Monad m => m Bool -> m Bool -> m Bool

    yjtools Data.Bool.Tools

    No documentation available.

  3. (.&.) :: Bits a => a -> a -> a

    base Data.Bits

    Bitwise "and"

  4. (<&>) :: Functor f => f a -> (a -> b) -> f b

    base Data.Functor

    Flipped version of <$>.

    (<&>) = flip fmap
    

    Examples

    Apply (+1) to a list, a Just and a Right:
    >>> Just 2 <&> (+1)
    Just 3
    
    >>> [1,2,3] <&> (+1)
    [2,3,4]
    
    >>> Right 3 <&> (+1)
    Right 4
    

  5. (.&.) :: Bits a => a -> a -> a

    base GHC.Bits

    Bitwise "and"

  6. (.&&.) :: (Testable prop1, Testable prop2) => prop1 -> prop2 -> Property

    QuickCheck Test.QuickCheck

    Conjunction: p1 .&&. p2 passes if both p1 and p2 pass.

  7. (.&.) :: (Testable prop1, Testable prop2) => prop1 -> prop2 -> Property

    QuickCheck Test.QuickCheck

    Nondeterministic choice: p1 .&. p2 picks randomly one of p1 and p2 to test. If you test the property 100 times it makes 100 random choices.

  8. (.&&.) :: (Testable prop1, Testable prop2) => prop1 -> prop2 -> Property

    tasty-quickcheck Test.Tasty.QuickCheck

    Conjunction: p1 .&&. p2 passes if both p1 and p2 pass.

  9. (.&.) :: (Testable prop1, Testable prop2) => prop1 -> prop2 -> Property

    tasty-quickcheck Test.Tasty.QuickCheck

    Nondeterministic choice: p1 .&. p2 picks randomly one of p1 and p2 to test. If you test the property 100 times it makes 100 random choices.

  10. (<&&=) :: MonadState s m => LensLike' ((,) Bool) s Bool -> Bool -> m Bool

    lens Control.Lens.Lens

    Logically && a Boolean valued Lens into your Monad's state and return the result. When you do not need the result of the operation, (&&=) is more flexible.

    (<&&=) :: MonadState s m => Lens' s Bool -> Bool -> m Bool
    (<&&=) :: MonadState s m => Iso' s Bool  -> Bool -> m Bool
    

Page 25 of many | Previous | Next