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Within LTS Haskell 24.3 (ghc-9.10.2)
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conduit Data.Conduit.Combinators Run a consuming conduit repeatedly, only stopping when there is no more data available from upstream. In contrast to peekForever, this function will ignore empty chunks of data. So for example, if a stream of data contains an empty ByteString, it is still treated as empty, and the consuming function is not called.
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conduit Data.Conduit.Internal Wait for input forever, calling the given inner Pipe for each piece of new input. Returns the upstream result type. Since 0.5.0
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haskell-gi Data.GI.CodeGen.API No documentation available.
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haskell-gi Data.GI.GIR.Arg No documentation available.
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JuicyPixels Codec.Picture The animation will restart once the end is reached
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JuicyPixels Codec.Picture.Gif The animation will restart once the end is reached
pubSubForever :: Connection -> PubSubController -> IO () -> IO ()hedis Database.Redis Open a connection to the Redis server, register to all channels in the PubSubController, and process messages and subscription change requests forever. The only way this will ever exit is if there is an exception from the network code or an unhandled exception in a MessageCallback or PMessageCallback. For example, if the network connection to Redis dies, pubSubForever will throw a ConnectionLost. When such an exception is thrown, you can recall pubSubForever with the same PubSubController which will open a new connection and resubscribe to all the channels which are tracked in the PubSubController. The general pattern is therefore during program startup create a PubSubController and fork a thread which calls pubSubForever in a loop (using an exponential backoff algorithm such as the retry package to not hammer the Redis server if it does die). For example,
myhandler :: ByteString -> IO () myhandler msg = putStrLn $ unpack $ decodeUtf8 msg onInitialComplete :: IO () onInitialComplete = putStrLn "Redis acknowledged that mychannel is now subscribed" main :: IO () main = do conn <- connect defaultConnectInfo pubSubCtrl <- newPubSubController [("mychannel", myhandler)] [] concurrently ( forever $ pubSubForever conn pubSubCtrl onInitialComplete `catch` (\(e :: SomeException) -> do putStrLn $ "Got error: " ++ show e threadDelay $ 50*1000) -- TODO: use exponential backoff ) $ restOfYourProgram {- elsewhere in your program, use pubSubCtrl to change subscriptions -}
At most one active pubSubForever can be running against a single PubSubController at any time. If two active calls to pubSubForever share a single PubSubController there will be deadlocks. If you do want to process messages using multiple connections to Redis, you can create more than one PubSubController. For example, create one PubSubController for each getNumCapabilities and then create a Haskell thread bound to each capability each calling pubSubForever in a loop. This will create one network connection per controller/capability and allow you to register separate channels and callbacks for each controller, spreading the load across the capabilities.pubSubForever :: Connection -> PubSubController -> IO () -> IO ()hedis Database.Redis.Sentinel Open a connection to the Redis server, register to all channels in the PubSubController, and process messages and subscription change requests forever. The only way this will ever exit is if there is an exception from the network code or an unhandled exception in a MessageCallback or PMessageCallback. For example, if the network connection to Redis dies, pubSubForever will throw a ConnectionLost. When such an exception is thrown, you can recall pubSubForever with the same PubSubController which will open a new connection and resubscribe to all the channels which are tracked in the PubSubController. The general pattern is therefore during program startup create a PubSubController and fork a thread which calls pubSubForever in a loop (using an exponential backoff algorithm such as the retry package to not hammer the Redis server if it does die). For example,
myhandler :: ByteString -> IO () myhandler msg = putStrLn $ unpack $ decodeUtf8 msg onInitialComplete :: IO () onInitialComplete = putStrLn "Redis acknowledged that mychannel is now subscribed" main :: IO () main = do conn <- connect defaultConnectInfo pubSubCtrl <- newPubSubController [("mychannel", myhandler)] [] concurrently ( forever $ pubSubForever conn pubSubCtrl onInitialComplete `catch` (\(e :: SomeException) -> do putStrLn $ "Got error: " ++ show e threadDelay $ 50*1000) -- TODO: use exponential backoff ) $ restOfYourProgram {- elsewhere in your program, use pubSubCtrl to change subscriptions -}
At most one active pubSubForever can be running against a single PubSubController at any time. If two active calls to pubSubForever share a single PubSubController there will be deadlocks. If you do want to process messages using multiple connections to Redis, you can create more than one PubSubController. For example, create one PubSubController for each getNumCapabilities and then create a Haskell thread bound to each capability each calling pubSubForever in a loop. This will create one network connection per controller/capability and allow you to register separate channels and callbacks for each controller, spreading the load across the capabilities.-
wai-app-static WaiAppStatic.Types essentially infinite caching; in reality, probably one year
serveForever :: SocketServer -> HandlerT -> IO ()MissingH Network.SocketServer Handle all incoming requests from the given SocketServer.