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  1. EmojiKeycapSequence :: Bool_

    text-icu Data.Text.ICU.Char

    See https://www.unicode.org/reports/tr51/#Emoji_Sets

  2. RgiEmojiFlagSequence :: Bool_

    text-icu Data.Text.ICU.Char

    See https://www.unicode.org/reports/tr51/#Emoji_Sets

  3. RgiEmojiModifierSequence :: Bool_

    text-icu Data.Text.ICU.Char

    See https://www.unicode.org/reports/tr51/#Emoji_Sets

  4. RgiEmojiTagSequence :: Bool_

    text-icu Data.Text.ICU.Char

    See https://www.unicode.org/reports/tr51/#Emoji_Sets

  5. RgiEmojiZwjSequence :: Bool_

    text-icu Data.Text.ICU.Char

    See https://www.unicode.org/reports/tr51/#Emoji_Sets

  6. u_ILLEGAL_ESCAPE_SEQUENCE :: ICUError

    text-icu Data.Text.ICU.Error

    No documentation available.

  7. u_REGEX_BAD_ESCAPE_SEQUENCE :: ICUError

    text-icu Data.Text.ICU.Error

    No documentation available.

  8. u_UNSUPPORTED_ESCAPE_SEQUENCE :: ICUError

    text-icu Data.Text.ICU.Error

    No documentation available.

  9. isSubsequenceOf :: Eq a => [a] -> [a] -> Bool

    ghc-internal GHC.Internal.Data.List

    The isSubsequenceOf function takes two lists and returns True if all the elements of the first list occur, in order, in the second. The elements do not have to occur consecutively. isSubsequenceOf x y is equivalent to x `elem` (subsequences y). Note: isSubsequenceOf is often used in infix form.

    Examples

    >>> "GHC" `isSubsequenceOf` "The Glorious Haskell Compiler"
    True
    
    >>> ['a','d'..'z'] `isSubsequenceOf` ['a'..'z']
    True
    
    >>> [1..10] `isSubsequenceOf` [10,9..0]
    False
    
    For the result to be True, the first list must be finite; for the result to be False, the second list must be finite:
    >>> [0,2..10] `isSubsequenceOf` [0..]
    True
    
    >>> [0..] `isSubsequenceOf` [0,2..10]
    False
    
    >>> [0,2..] `isSubsequenceOf` [0..]
    * Hangs forever*
    

  10. subsequences :: [a] -> [[a]]

    ghc-internal GHC.Internal.Data.List

    The subsequences function returns the list of all subsequences of the argument.

    Laziness

    subsequences does not look ahead unless it must:
    >>> take 1 (subsequences undefined)
    [[]]
    
    >>> take 2 (subsequences ('a' : undefined))
    ["","a"]
    

    Examples

    >>> subsequences "abc"
    ["","a","b","ab","c","ac","bc","abc"]
    
    This function is productive on infinite inputs:
    >>> take 8 $ subsequences ['a'..]
    ["","a","b","ab","c","ac","bc","abc"]
    

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