Hoogle Search

Within LTS Haskell 24.4 (ghc-9.10.2)

Note that Stackage only displays results for the latest LTS and Nightly snapshot. Learn more.

  1. map :: (a -> b) -> [a] -> [b]

    ghc-internal GHC.Internal.Data.List

    map f xs is the list obtained by applying f to each element of xs, i.e.,

    map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn]
    map f [x1, x2, ...] == [f x1, f x2, ...]
    
    this means that map id == id

    Examples

    >>> map (+1) [1, 2, 3]
    [2,3,4]
    
    >>> map id [1, 2, 3]
    [1,2,3]
    
    >>> map (\n -> 3 * n + 1) [1, 2, 3]
    [4,7,10]
    

  2. map :: (a -> b) -> [a] -> [b]

    ghc-internal GHC.Internal.Data.OldList

    map f xs is the list obtained by applying f to each element of xs, i.e.,

    map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn]
    map f [x1, x2, ...] == [f x1, f x2, ...]
    
    this means that map id == id

    Examples

    >>> map (+1) [1, 2, 3]
    [2,3,4]
    
    >>> map id [1, 2, 3]
    [1,2,3]
    
    >>> map (\n -> 3 * n + 1) [1, 2, 3]
    [4,7,10]
    

  3. map :: (a -> b) -> [a] -> [b]

    ghc-internal GHC.Internal.List

    map f xs is the list obtained by applying f to each element of xs, i.e.,

    map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn]
    map f [x1, x2, ...] == [f x1, f x2, ...]
    
    this means that map id == id

    Examples

    >>> map (+1) [1, 2, 3]
    [2,3,4]
    
    >>> map id [1, 2, 3]
    [1,2,3]
    
    >>> map (\n -> 3 * n + 1) [1, 2, 3]
    [4,7,10]
    

  4. map :: (a -> b) -> Infinite a -> Infinite b

    infinite-list Data.List.Infinite

    Apply a function to every element of an infinite list.

  5. map :: (Char -> Char) -> JSString -> JSString

    jsaddle Data.JSString

    O(n) map f t is the JSString obtained by applying f to each element of t. Subject to fusion. Performs replacement on invalid scalar values.

  6. map :: (Char -> Char) -> Stream Char -> Stream Char

    jsaddle Data.JSString.Internal.Fusion.Common

    O(n) map f xs is the Stream Char obtained by applying f to each element of xs. Properties

    unstream . map f . stream = map f
    

  7. map :: (a -> b) -> [a] -> [b]

    numeric-prelude NumericPrelude

    map f xs is the list obtained by applying f to each element of xs, i.e.,

    map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn]
    map f [x1, x2, ...] == [f x1, f x2, ...]
    
    this means that map id == id

    Examples

    >>> map (+1) [1, 2, 3]
    [2,3,4]
    
    >>> map id [1, 2, 3]
    [1,2,3]
    
    >>> map (\n -> 3 * n + 1) [1, 2, 3]
    [4,7,10]
    

  8. map :: (a -> b) -> [a] -> [b]

    numeric-prelude NumericPrelude.Base

    map f xs is the list obtained by applying f to each element of xs, i.e.,

    map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn]
    map f [x1, x2, ...] == [f x1, f x2, ...]
    
    this means that map id == id

    Examples

    >>> map (+1) [1, 2, 3]
    [2,3,4]
    
    >>> map id [1, 2, 3]
    [1,2,3]
    
    >>> map (\n -> 3 * n + 1) [1, 2, 3]
    [4,7,10]
    

  9. map :: (a -> b) -> [a] -> [b]

    numhask NumHask.Prelude

    map f xs is the list obtained by applying f to each element of xs, i.e.,

    map f [x1, x2, ..., xn] == [f x1, f x2, ..., f xn]
    map f [x1, x2, ...] == [f x1, f x2, ...]
    
    this means that map id == id

    Examples

    >>> map (+1) [1, 2, 3]
    [2,3,4]
    
    >>> map id [1, 2, 3]
    [1,2,3]
    
    >>> map (\n -> 3 * n + 1) [1, 2, 3]
    [4,7,10]
    

  10. map :: (k -> p -> v -> w) -> HashPSQ k p v -> HashPSQ k p w

    psqueues Data.HashPSQ

    O(n) Modify every value in the queue.

Page 25 of many | Previous | Next