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Within LTS Haskell 24.64 (ghc-9.10.3)

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  1. (.:!=) :: FromJSON a => Object -> Key -> Parser a

    aeson Data.Aeson.Types

    Retrieve the value associated with the given key of an Object. If the key is not present and the omittedField is Just x for some x, the result will be that x. This differs from .:?= by attempting to parse Null the same as any other JSON value, instead of using omittedField when it's Just.

  2. (.:?) :: FromJSON a => Object -> Key -> Parser (Maybe a)

    aeson Data.Aeson.Types

    Retrieve the value associated with the given key of an Object. The result is Nothing if the key is not present or if its value is Null, or empty if the value cannot be converted to the desired type. This accessor is most useful if the key and value can be absent from an object without affecting its validity. If the key and value are mandatory, use .: instead.

  3. (.:?=) :: FromJSON a => Object -> Key -> Parser a

    aeson Data.Aeson.Types

    Retrieve the value associated with the given key of an Object. If the key is not present or the field is null and the omittedField is Just x for some x, the result will be that x.

  4. (.=) :: (KeyValue e kv, ToJSON v) => Key -> v -> kv

    aeson Data.Aeson.Types

    No documentation available.

  5. (.?=) :: (KeyValueOmit e kv, ToJSON v) => Key -> v -> kv

    aeson Data.Aeson.Types

    No documentation available.

  6. (.&&.) :: (Testable prop1, Testable prop2) => prop1 -> prop2 -> Property

    tasty-quickcheck Test.Tasty.QuickCheck

    Conjunction: p1 .&&. p2 passes if both p1 and p2 pass.

  7. (.&.) :: (Testable prop1, Testable prop2) => prop1 -> prop2 -> Property

    tasty-quickcheck Test.Tasty.QuickCheck

    Nondeterministic choice: p1 .&. p2 picks randomly one of p1 and p2 to test. If you test the property 100 times it makes 100 random choices.

  8. (.||.) :: (Testable prop1, Testable prop2) => prop1 -> prop2 -> Property

    tasty-quickcheck Test.Tasty.QuickCheck

    Disjunction: p1 .||. p2 passes unless p1 and p2 simultaneously fail.

  9. (.*>) :: ByteString -> Parser a -> Parser a

    attoparsec Data.Attoparsec.ByteString.Char8

    Deprecated: This is no longer necessary, and will be removed. Use *> instead.

  10. (.*>) :: Text -> Parser a -> Parser a

    attoparsec Data.Attoparsec.Text

    Deprecated: This is no longer necessary, and will be removed. Use *> instead.

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