Hoogle Search
Within LTS Haskell 24.33 (ghc-9.10.3)
Note that Stackage only displays results for the latest LTS and Nightly snapshot. Learn more.
-
dimensional Numeric.Units.Dimensional.Prelude (++) appends two lists, i.e.,
[x1, ..., xm] ++ [y1, ..., yn] == [x1, ..., xm, y1, ..., yn] [x1, ..., xm] ++ [y1, ...] == [x1, ..., xm, y1, ...]
If the first list is not finite, the result is the first list.Performance considerations
This function takes linear time in the number of elements of the first list. Thus it is better to associate repeated applications of (++) to the right (which is the default behaviour): xs ++ (ys ++ zs) or simply xs ++ ys ++ zs, but not (xs ++ ys) ++ zs. For the same reason concat = foldr (++) [] has linear performance, while foldl (++) [] is prone to quadratic slowdownExamples
>>> [1, 2, 3] ++ [4, 5, 6] [1,2,3,4,5,6]
>>> [] ++ [1, 2, 3] [1,2,3]
>>> [3, 2, 1] ++ [] [3,2,1]
-
distribution-opensuse OpenSuse.Prelude (++) appends two lists, i.e.,
[x1, ..., xm] ++ [y1, ..., yn] == [x1, ..., xm, y1, ..., yn] [x1, ..., xm] ++ [y1, ...] == [x1, ..., xm, y1, ...]
If the first list is not finite, the result is the first list.Performance considerations
This function takes linear time in the number of elements of the first list. Thus it is better to associate repeated applications of (++) to the right (which is the default behaviour): xs ++ (ys ++ zs) or simply xs ++ ys ++ zs, but not (xs ++ ys) ++ zs. For the same reason concat = foldr (++) [] has linear performance, while foldl (++) [] is prone to quadratic slowdownExamples
>>> [1, 2, 3] ++ [4, 5, 6] [1,2,3,4,5,6]
>>> [] ++ [1, 2, 3] [1,2,3]
>>> [3, 2, 1] ++ [] [3,2,1]
-
extrapolate Test.Extrapolate Lazily interleaves two lists, switching between elements of the two. Union/sum of the elements in the lists.
[x,y,z,...] +| [a,b,c,...] = [x,a,y,b,z,c,...]
-
extrapolate Test.Extrapolate.Core Lazily interleaves two lists, switching between elements of the two. Union/sum of the elements in the lists.
[x,y,z,...] +| [a,b,c,...] = [x,a,y,b,z,c,...]
(
+++ ) :: Ord a => [a] -> [a] -> [a]extrapolate Test.Extrapolate.Utils No documentation available.
-
faktory Faktory.Prelude (++) appends two lists, i.e.,
[x1, ..., xm] ++ [y1, ..., yn] == [x1, ..., xm, y1, ..., yn] [x1, ..., xm] ++ [y1, ...] == [x1, ..., xm, y1, ...]
If the first list is not finite, the result is the first list.Performance considerations
This function takes linear time in the number of elements of the first list. Thus it is better to associate repeated applications of (++) to the right (which is the default behaviour): xs ++ (ys ++ zs) or simply xs ++ ys ++ zs, but not (xs ++ ys) ++ zs. For the same reason concat = foldr (++) [] has linear performance, while foldl (++) [] is prone to quadratic slowdownExamples
>>> [1, 2, 3] ++ [4, 5, 6] [1,2,3,4,5,6]
>>> [] ++ [1, 2, 3] [1,2,3]
>>> [3, 2, 1] ++ [] [3,2,1]
type family (xs :: [α])
++ (ys :: [α]) :: [α]fixed-vector-hetero Data.Vector.HFixed.Class Concaternation of type level lists.
type family (xs :: [α])
++ (ys :: [α]) :: [α]fixed-vector-hetero Data.Vector.HFixed.TypeFuns Concaternation of type level lists.
-
hledger-web Hledger.Web.Import (++) appends two lists, i.e.,
[x1, ..., xm] ++ [y1, ..., yn] == [x1, ..., xm, y1, ..., yn] [x1, ..., xm] ++ [y1, ...] == [x1, ..., xm, y1, ...]
If the first list is not finite, the result is the first list.Performance considerations
This function takes linear time in the number of elements of the first list. Thus it is better to associate repeated applications of (++) to the right (which is the default behaviour): xs ++ (ys ++ zs) or simply xs ++ ys ++ zs, but not (xs ++ ys) ++ zs. For the same reason concat = foldr (++) [] has linear performance, while foldl (++) [] is prone to quadratic slowdownExamples
>>> [1, 2, 3] ++ [4, 5, 6] [1,2,3,4,5,6]
>>> [] ++ [1, 2, 3] [1,2,3]
>>> [3, 2, 1] ++ [] [3,2,1]
(
+=. ) :: forall v typ . PersistField typ => EntityField v typ -> typ -> Update vhledger-web Hledger.Web.Import Assign a field by addition (+=).
Examples
addAge :: MonadIO m => ReaderT SqlBackend m () addAge = updateWhere [UserName ==. "SPJ" ] [UserAge +=. 1]
The above query when applied on dataset-1, will produce this:+-----+-----+---------+ |id |name |age | +-----+-----+---------+ |1 |SPJ |40 -> 41 | +-----+-----+---------+ |2 |Simon|41 | +-----+-----+---------+